Math, asked by sushilbayen1624, 13 days ago

A can do a piece of work in 6 days B in 9 days and C in 12 days. A and B starts the work together but after 2 days B had left and C joint with A till the completion of the work. How long did the work last?


Answered by AyushCristiano


Step-by-step explanation:

They all in 2 days do=2x(1/6+1/9+1/12) part=13/18 part. B leaves.

Part of work left=1-13/18 part=5/18 part

C and A in 1 day do=(1/6+1/12) part=1/4 part

They can do 5/18 of the work in (5/18)x4 days=10/9 days

The work last for = 2+10/9 days=3 and 1/2 days

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