Question

A can do a piece of work in 6 days while A and B can do it together in 2 days. How many days will be taken by B to complete the work alone?​

Answer 1

Answer:

3 days

Step-by-step explanation:

LCM of 6 and 2 = 6 = Total work . efficiency of A+B = 6/2 = 3 unit / day. so, efficiency of B = (A+B) - A = 3-1 = 2 unit/day . time taken by B to complete whole work = 6/2 = 3 days .

Answer 2

Answer:

Given :-

• A can do a work in = 6 days .
• A+B can do the same job in = 2 days .

To Find :-

• Time taken by B to do same work alone ?

Solution :-

LCM of 6 and 2 = 6 = Total work .

efficiency of A = 6/6 = 1 unit / day

efficiency of A+B = 6/2 = 3 unit / day.

so, efficiency of B = (A+B) - A = 3-1 = 2 unit/day .

time taken by B to complete whole work = 6/2 = 3 days .

Hence , B will take 3 days alone to do whole work .

Step-by-step explanation:

Hope it helps!