A can do a piece of work in 6 hours while B alone can do it in 16 hours. If A, B and C working together can finish it in 8 hours, in how many hours can C alone finish the work
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We will solve this using the LCM technique.
A takes 6 days & B takes 8 days. So, let the total work be LCM(6,8) = 24 Units
A -> 6 days = 4 Units/day
B -> 8 days = 3 Units/day
A + B = 7 Units/day
Thus, TOTAL TIME = 247247 = 10301.9583 Days (Answer)
A takes 6 days & B takes 8 days. So, let the total work be LCM(6,8) = 24 Units
A -> 6 days = 4 Units/day
B -> 8 days = 3 Units/day
A + B = 7 Units/day
Thus, TOTAL TIME = 247247 = 10301.9583 Days (Answer)
vishrut2712:
its wrong answer
:( :(
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