a can do a piece of work in 60 days. he work for 15 days and then B done finish the remaining work in 30 days. The two together can finish the work in how many days
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a can do a piece of work in 60 days
in 15 days he work 1/4th part of net work
hence remains 3/4th part of work finish by B in 30 days
so, B can do a piece of work in 40 days
both work together in 60x40/60+100=24 days
in 15 days he work 1/4th part of net work
hence remains 3/4th part of work finish by B in 30 days
so, B can do a piece of work in 40 days
both work together in 60x40/60+100=24 days
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Answer:
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Step-by-step explanation:
24 days
A can do (1/60)th of the work in a day. So in 15 days, A does 15*1/60 = 1/4th of the work.
The remaining 3/4th of the work is done by B in 30 days. So the entire work would be done by B in 30*4/3 = 40 days.
So if A and B together do the work they will do (1/60)+(1/40) = (2+120)+(3/120) = 5/120 or 1/24th of the work in a day.
So A and B together will do the same work in 24 days.
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