Math, asked by shashwatnarayan007, 2 months ago

A can do a piece of work in 60 days. He
work for 15 days and then B done finish the
remaining work in 30 days. The two
together can finish the work in how many
days?
(b) 10
(c) 12
(d) 24
10 days, if a
(a) 7​

Answers

Answered by nattkudrat
1

Answer:

(d) 24

Step-by-step explanation:

A can do (1/60)th of the work in a day. So in 15 days, A does 15*1/60 = 1/4th of the work.

The remaining 3/4th of the work is done by B in 30 days. So the entire work would be done by B in 30*4/3 = 40 days.

So if A and B together do the work they will do (1/60)+(1/40) = (2+120)+(3/120) = 5/120 or 1/24th of the work in a day.

So A and B together will do the same work in 24 days.

Hope it helps you in understanding!

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Answered by THUNDERBOLT007
0

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A can do (1/60)th of the work in a day. So in 15 days, A does 15*1/60 = 1/4th of the work.

The remaining 3/4th of the work is done by B in 30 days. So the entire work would be done by B in 30*4/3 = 40 days.

So if A and B together do the work they will do (1/60)+(1/40) = (2+120)+(3/120) = 5/120 or 1/24th of the work in a day.

So A and B together will do the same work in 24 days.

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