A can do a piece of work in 60 days, which B can do in 40 days. Both started the work but A left 10 days before the completion of the work. The work was finished in how many days?
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Answer:
28 days
Step-by-step explanation:
A left the job 10 days before the completion. So, B worked alone for the last 10 days. First, we will calculate B’s 10 days work, which he did alone.
In 10 days B will do 10 × 1/40 = 1/4th of the work.
Remaining work 1 - ¼ = ¾ (Which A and B have done together). A and B can do 1/60 + 1/40 work in 1 day. Their one-day’s work is 1/60 + 1/40 = (2 + 3)/120 = 5/120 = 1/24. They can finish the work in 24 days.
They would have done three-fourth of the work in 24 × 3/4 = 18 days.
⇒ Total days = 18 + 10 = 28
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