A can do a piece of work in 60 days, which b can do in 40 days. Both started the work but a left 10 days before the completion of the work. The work was finished in how many days?
Answers
Solution:
A's 1 day work = 1/60
B's 1 day work = 1/40
Together they can finish in = 1/60 + 1/40 = 1/24
Therefore, together they take 24 days to complete the work.
Now, if A left 10 days before completion then,
Number of days A & B worked together = 24-10 = 14 days.
Percent completion of both A & B working together for 14 days is,
(1/24) × 14 × 100 = 58.33%
B's 1 day efficiency = 1/40 ×100 = 2.5%
& the left work is = 100 - 58.33 = 41.67%
Therefore, no. of days further B will take to complete the work is,
41.67/2.5 = 16.67 days
Therefore, the work finished at 14+16.67 = 30.67 days.
The number of day work finished at 30.67 days when a can complete a task in 60 days but b can complete it in 40.
Given that,
A can complete a task in 60 days but b can complete it in 40. Both began the work, but one left ten days before it was finished.
We have to find how many days did it take to complete the work.
We know that,
A's 1 day work = 1/60
B's 1 day work = 1/40
Together they can finish in = 1/60 + 1/40 = 1/24
Together, they finish the work in 24 days.
Then, if A left 10 days before the project was finished,
24- 10 = 14 days were spent working together by A and B.
The percentage of time that both A and B spent collaborating for 14 days is, (1/24) × 14 × 100 = 58.33%
B's 1 day efficiency = 1/40 ×100 = 2.5%
The left work = 100 - 58.33 = 41.67%
Number of days further B will take to complete the work is,
41.67/2.5 = 16.67 days
Work finished at 14+16.67 = 30.67 days.
Therefore, the number of day work finished at 30.67 days when a can complete a task in 60 days but b can complete it in 40.
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