Math, asked by paramveer244, 9 months ago

A can do a piece of work in 70 days and B is 40% more efficient than A. The number
of days taken by B to do the same work will be?​

Answers

Answered by jaskawal
5

Answer:

A do the work = 70days

40%of70=40 / 100×70

40%of70=28

Bdo the work=70-28= 42

B do the same work in 42 days

Step-by-step explanation:

Hope it helps

Answered by jithinrajrajan96
3

Answer:

42

Step-by-step explanation:

b is 40%more efficient than a

40 percent of 70 is 28

70-28 is 42

b does the work in 42

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