A can do a piece of work in 8 days which b can destroy in 3 days. A has worked for 6 days, duoring the last 2 days of which b has been destroying how many days must a now work alone to complete the work?
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Answer:
7.33 days
Step-by-step explanation:
Let say W is the work
A do in 8 days = W
A do in 6 days = (W/8)*6=3W/4
B destroy in 3 day = W
B destroy in 2 days = 2W/3
Work = 3W/4 -2W/3
=(1/12)*(9W-8W) =W/12
1/12 work is done.
Remaining work to be done
W- W/12 = 11W/12
W is done in 8 days
11W/12 is done in = (8/W)*(11W/12)
88/12 =22/3 = 7.33 days
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