a can do a piece of work in 80 days he works at it for 10 days and then B alone finish the work in 40 days the number of days taken by two together to finish the work is
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Question :-
- a can do a piece of work in 80 days he works at it for 10 days and then B alone finish the work in 42 days the number of days taken by two together to finish the work is
Concept :-
- first, we'll find A's work in 1 day and in 10 days then we will find the remaining A's work.
- Second, we'll find the number of days took for B to complete the whole work.
- we will find the total number of days taken by both of them to finish the whole work.
Solution :-
A's work in 1 day = 1/80
A's work in 10 days = 1/80 × 10 = 1/8
A's remaining work = 1 - 1/8 = 7/8
Total number of days taken by B to complete the whole work = 40 × 8/7 = 48 days.
Therefore, B completed the whole work in 48 days.
Therefore, B's work in 1 day = 1/48
( A + B )'s 1 day work = 1/80 + 1/48 = 3+5/240 = 8/240 = 1/30
Therefore, they can finish the whole work in 30 days.
Joyful learning!!!⛅
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