A can do a piece of work in 80 days. He works at it for 10 days and then B alone finishes the remaining work in 42 days. In how many days could both do it??
Answers
Answered by
7
A can do a work in 80 days implies he can do 1/80th part of a work in 1 day. so if he works for 10 such days.. he would complete 10"1/80th part of work I e 1/8th part of work.
work remaining= 7/8th
b completes 7/8th work in 42 days.
dividing both the sides by 7, we get
b can complete 1/8th if his work in 42/7=6 days
now multiplying by 8 on both sides we get,
b can complete the full work alone in 6×8=48 days.
so b can complete 1/48th part of work in 1 day.
when a and b work together in 1 day they can do a work of 1/80 + 1/48 = 1/30
so both together can complete 1/30th part of work in 1 day.
which implies if they work together they can complete the work in 30 days
work remaining= 7/8th
b completes 7/8th work in 42 days.
dividing both the sides by 7, we get
b can complete 1/8th if his work in 42/7=6 days
now multiplying by 8 on both sides we get,
b can complete the full work alone in 6×8=48 days.
so b can complete 1/48th part of work in 1 day.
when a and b work together in 1 day they can do a work of 1/80 + 1/48 = 1/30
so both together can complete 1/30th part of work in 1 day.
which implies if they work together they can complete the work in 30 days
ruprekha11:
I am in kolkata
Answered by
47
Hi friend...
Here is your answer
SOLUTION ==
A completes in 10 days 10/80 or 1/8 of the work.
The remaining work 7/8 is completed by B in 42 days.
Therefore, to complete the whole work B would take (8/7)*42 =48 days.
Now, if A and B work together, they can complete in (80*48)/(80+48) = 30 days
I hope it will help you
#yahyaahmad#
Here is your answer
SOLUTION ==
A completes in 10 days 10/80 or 1/8 of the work.
The remaining work 7/8 is completed by B in 42 days.
Therefore, to complete the whole work B would take (8/7)*42 =48 days.
Now, if A and B work together, they can complete in (80*48)/(80+48) = 30 days
I hope it will help you
#yahyaahmad#
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