Math, asked by Hahao3417, 1 year ago

A can do a piece of work in 80 days i work for 10 days and b alone finish the remaining work 42 days in how many days could would do it

Answers

Answered by sonabrainly
4

Answer:

Step-by-step explanation:

do part of park in 1 day=1/80

Work done by ajay in 10 days=10/80

=1/8

Remaining work=1-1/8

=7/8

B complete in 42 days=7/8part of work

B can complete in1day=1/48part of work

So B alone can complete it in 48 days

Work done by both in 1 day

=1/80+1/48

=(3+5)/240

=1/30

So they can finish the work together in 30days

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