Question

A can do a piece of work in 80days.He works at it for 10days and then b alone finishes the remaining work in 42 days .In how much time will a and b, working together ,finish the work?

Answer 1

Answer : A can complete a piece of work in 80 days.In one day he completes the work=1/80th

10 days ,the part of work he did =10*1/80=10/80=1/8th

Balance work=1–1/8=7/8th and B completed in 42 days.

In one day B can do=(7/8)/42=1/48

Both A&B combine to do the work in one day=1/80+1/48=(3+5)/240=8/240=1/30

A & B together can complete the work in 30 days.

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