*A* can do a piece of work in 9 days while *B* can do it in 6 days and with the help of *C* they finish the work in 3 days . In how many days *C* can finish the work alone ?
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0
Answer:
hoccyoogyogygyo9g69g6
Answered by
1
Answer:
Work done by A in 1 day =
9
1
Work done by B in 1 day =
18
1
Work done by B in last 3 days =
18
1
×3=
6
1
Remaining work=1−
6
1
=
6
5
Work done by A and B in 1 day =
9
1
+
18
1
=
18
3
=
6
1
Hence no. of days in which A and B worked together is =
6
1
6
5
=5 days
Then total time to complete the work =3+5=8 days.
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