Question

A can do a piece of work in a 10 days and B in 20 days.
They begin together but A leaves two days before the
completion of the work. In how many days will
the whole work be completed.


please answer the question​

Answer 1

Answer:

A can do the work in 10 days

B can do the work in 20 days

Therefore, their efficiencies

Total work = LCM(10,20)= 20 units

A's efficiency= 20/10= 2 units of work/day

B's efficiency= 20/20= 1 unit of work / day

So, according to the question

It takes n days to complete the total job and A leaves 2 days early. So A works for n-2 days and B works for n days

So, A's work in n-2 days + B's work in n days = 20 units

Or, 2(n-2) + 1(n)= 20

Or, n= 8 days

So, the work gets completed in 8 days.

Step-by-step explanation:

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