* A can do a piece of work in the same time in which B and C together can do it. If A and B together can do it in 10 days and C alone in 50 days, in how many days can B alone do it?
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Explanation : (A + B)'s 1 day's work =
10
1
C's 1 day's work =
50
1
(A + B + C)'s 1 day's work =
10
1
+
50
1
=
50
6
=
25
3
. .... (i)
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
From (i) and (ii) we get:
2 x (A's 1 day's work) =
25
3
A's 1 day's work =
50
3
.
B's 1 day's work
10
1
-
50
3
=
25
1
So B alone could do the work in 25 days.
Answer By shreyas
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Answer:
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