Math, asked by susuki8441, 1 year ago

A can do a piece work in 120 days and b can do it in 150 days. they work together for 20 days. then b leaves and a continues the work alone, 12 days after that c joins a and the work is completed in 48 days more. in how many days can c do it if he works alone?

Answers

Answered by Barbiebaby
37
I think that the answer will be 240 days
Answered by inderbanjar
33

A one days work = 1/120

B one days work = 1/150

(A+B) one days = 1/120+1/150=3/200

(A+B) 20 day work =3/200×20=3/10

A s 12 days work =1/120×12=1/10

C join =3/10+1/10=2/5

Ramining work =(1-2)/5=3/5

(A+C)48 days work =3/5×1/48=1/80

C one days work =1/80-1/20=1/240

C days=240 Ans

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