Question

A can do a piece work in 20 days B can do the same work in 25 days they work together for 5 days and the B leave in how many will A finish the remaining work ​

Answer 1

SOLUTION:-

Given:

A can do a piece of work in 20 days, B can do the same work in 25 days they work together for 5 days & B leave.

To find:

A finish the remaining work.

Explanation:

A is 1 days work= 1/20

B is 1 days work= 1/25

&

They work together;

(A's + B's) 1 days work

$= > ( \frac{1}{20} + \frac{1}{25} ) \\ \\ = > \frac{4 + 5}{100} \\ \\ = > \frac{9}{100}$

Therefore,

(A's + B's) 5 days work:

$= > \frac{9}{100} \times 5 \\ \\ = > \frac{9}{20}$

Remaining work:

$= > 1 - \frac{9}{20} \\ \\ = > \frac{20 - 9}{20} \\ \\ = > \frac{11}{20}$

So,

A's finishes the whole work in 20 days.

A's finishes 11/20 of the work;

$= > (20 \times \frac{11}{20} ) \ \: days \\ \\ = > 11 \: days$

Hence,

A's finishes the remaining work in 11 days.

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