Question

A can do a work in 10 days and B can do it in 15 days. They worked together for 4 days and then A left the work . In

how many days can B finish the remaining work?

ANSWER CORRECTLY
(EXPLANATION)​

Answer 1

Step-by-step explanation:

1. work done =1/A+1/B
2. 1/10+1/15=3/30+2/30=5/30=1/6
3. now we should reciprocal 1/6=6
4. A ,B combine to do the work =6 days
5. already A done the 4days work then the remaining work B should done by 4-6=2days
6. A=4days,B=2days

Answer 2

Answer:

5 days

Step-by-step explanation:

Work to be done = x

work x done by A in days = 10

work done by A in one day is 1/10 = 3/30

work x done by B in days = 15

work done by B in one day is 1/15 = 2/30

LCM of 10 and 15 = 30

Work done by A in 4 days = $\frac{3*4}{30}$ = $\frac{12}{30}$

Work done by B in 4 days = $\frac{2*4}{30}$ = $\frac{8}{30}$

Total work done in 4 days = $\frac{12}{30}+\frac{8}{30} = \frac{20}{30}$

Work left = $\frac{10}{30}$

Time taken by B to complete the task is $\frac{10/2}{30/30} =5$