Math, asked by missankita54, 4 months ago

'A' can do a work in 10days and 'B' can do the same work in 16days . with the help of C they do the work in 4 days only. in how many days 'C can do the work alone ?​

Answers

Answered by Anonymous
13

Step-by-step explanation:

A can do the work in = 10 days

work done by A in one day = 1/10

B can do the work in = 16 days

work done by B in one day = 1/16

work done by A and B in one day (A+B) = 1/10+1/16

= 8+5/80. => 13/80

A, B,C can do the work in = 4 days

work done by A, B, C in one day = 1/4

so, the work done by C in one day =( A+B+C)-(A+B)

=> 1/4 - 13/80. => (20-13)/80.

=> 7/80

so, C can do the work alone in = 80/7

=> 11 3/7 days.

I hope it will help you sister.

Answered by jiyagodhwani101
0

Answer:

hello Ankita!!

kese ho?

after long time me active aayi.

muje bhul toh nahi gaye na??

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