Math, asked by aaaayush505, 4 months ago

A can do a work in 12 days and B can do the same work in 4days. they worked together for only 1day and then B leaves the work. In how many days will A complete the remaining work? ​


aaaayush505: sure

Answers

Answered by meherg21
0

Answer:

A can finish work in 18 days.

Step-by-step explanation:

A can finish work in 18 days.

It means A can do the work in one day = 1/18 part

B can finish it in 15 days.

It means B can do the work in one day = 1/15 part

B worked alone for 10 days and then left the job

Thus in 10 days B has completed part of work =

1/15 × 10 = 10/15 part or 2/3 part of work

Remaining work left = 1 - 2/3 = 1/3 part of work remaining

A can do 1/18 part in one day

Therefore 1/3 part will be completed by him

= 1/1/18 × 1/3

= 1/3 × 18/1

= 18/3 days

= 6 days

A alone will complete the work in 6 days

Answer : A alone will finish the work in 6 days


aaaayush505: Yes, I did the same but there is showing that the answer will be 1 day
meherg21: your question and my answer has difference but I think method is same so please try yourself
aaaayush505: yes I know that
meherg21: so try and check your answer and tell me is it right method
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