Question

A can do a work in 12 days when he had worked for 3 days , b joined him .If they complete the work in 3 days more.In how many days b alone complete

Answer 1

Hope it helps you.....

Answer 2

$A \:can \: complete \:a \:work \: in \: 12 \:days$

$A's \: one \:day \:work = \frac{1}{12} \: --(1)$

$A's \: 3 \:days \: work = \frac{3}{12} \\= \frac{1}{4}$

$Remaining \:work = 1 - \frac{1}{4} \\= \frac{4-1}{4} \\= \frac{3}{4}$

/* According to the problem given */

$As \:(A+B) \: complete \:the \:\frac{3}{4} \:work \\3 \:days$

$\therefore \: (A+B)'s \:complete \:the \:whole \:work \\</p><p>in \: 3 \times \frac{4}{3} = 4 \:days$

$(A+B)'s \: one \: days \:work = \frac{1}{4} \:--(2)$

$B's \: 1 \:day \: work\\ = (A+B)'s \: one \: days \:work - A's \:one \:days \:work \\= \frac{1}{4} - \frac{1}{12} \\= \frac{3-1}{12} \\= \frac{2}{12} \\= \frac{1}{6}$

$Hence, B \:can \: complete \:the \:work \\in \: 6 \:days$

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