Question

A can do a work in 14 days and working together a and b can do the same work in 10 days. in what time can be alone do the work ?

Answer 1

4A can do a piece of work in 14 days
One day work of A=
$\frac{1}{14}$
Let the one day work of B be x.
(A+B) one day work =
$\frac{1}{10}$
A/q
$\frac{1}{14} + x = \frac{1}{10} \\ x = \frac{1}{10} - \frac{1}{14} \\ x = \frac{7 - 5}{70} = \frac{2}{70} = \frac{1}{35}$
Hence,B can do it in 35 days..

Answer 2

Given, Chocolate Concept

A=14 days

A+B=10 days

LCM(14,10)= 70 (=Total work)

One day work of A = 70÷14 = 5 (efficiency)

One day work of (A+B) = 70÷ 10 = 7 (efficiency)

We get, A+B= 7 ....(since w.k.t A=5)

=>5+B=7

=>B=2 (one day work of B)

w.k.t,

No. Of Days = Total work ÷Efficiency

= 70÷2 =35days

B alone can complete the work in 35 days..