A can do a work in 15 days and B in 20 days. If they together work on it for 4 days, then the fraction of the work done is
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Answered by
5
ANSWER::))
>>Take LCM of 15 and 20 as the total amount of work which is 60 units in this case.
>>A can do work in 15 days therefore amount of work done by A in 1 day is 60/15 = 4 units
>>B can do work in 15 days therefore amount of work done by A in 1 day is 60/20 = 3 units
>>Total amount of work done in 1 day =A work of 1 day+B's work of 1 day=4 units +3 units=7 units
>>Amount of work done in 4 days =4*7=28 units
>>Amount of Work Left = 60–28=32 units
>>Fraction of work left = Amount of work left/ >>Total Work = 32/60 = 8/15.
Step-by-step explanation:
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Answered by
2
Answer:
A do a work in 15 days
so, A's 1 say work =1/15
B do a work in 20 days
so, B's 1 day work =1/20
(A+B)'s 1 day work= 1/15+1/20
= (4+3)/60
=7/60
its 4 day work= 7/60×4
=7/15
total work =1÷7/15
=1×15/7
= 15/7
= 2 1/7
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