A can do a work in 15 days and B in 20 days if they work on together for 4 days then the fraction of the work that is left is
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Solution:-
A can do a piece of work in 15 days.
One day work of A =1/15
B can do a piece of work in 20 days
One day work of B =1/20
(A+B)'s one day work=
![= > \frac{1}{15} + \frac{1}{24} \\ = > \frac{4 + 3}{60} \\ = > \frac{7}{60} = > \frac{1}{15} + \frac{1}{24} \\ = > \frac{4 + 3}{60} \\ = > \frac{7}{60}](https://tex.z-dn.net/?f=+%3D++%26gt%3B++%5Cfrac%7B1%7D%7B15%7D++%2B++%5Cfrac%7B1%7D%7B24%7D++%5C%5C++%3D++%26gt%3B++%5Cfrac%7B4+%2B+3%7D%7B60%7D++%5C%5C++%3D++%26gt%3B++%5Cfrac%7B7%7D%7B60%7D+)
They work for 4 days.
![= > \frac{7}{60} \times 4 \\ = > \frac{7}{15} = > \frac{7}{60} \times 4 \\ = > \frac{7}{15}](https://tex.z-dn.net/?f=+%3D++%26gt%3B++%5Cfrac%7B7%7D%7B60%7D++%5Ctimes+4+%5C%5C++%3D++%26gt%3B++%5Cfrac%7B7%7D%7B15%7D+)
So,7/15 of the work is done by A and B
Remain work=
![= > 1 - \frac{7}{15} \\ = > \frac{15 - 7}{15} \\ = > \frac{8}{15} = > 1 - \frac{7}{15} \\ = > \frac{15 - 7}{15} \\ = > \frac{8}{15}](https://tex.z-dn.net/?f=+%3D++%26gt%3B+1+-++%5Cfrac%7B7%7D%7B15%7D++%5C%5C++%3D++%26gt%3B++%5Cfrac%7B15+-+7%7D%7B15%7D++%5C%5C++%3D++%26gt%3B++%5Cfrac%7B8%7D%7B15%7D+)
Hence,8/15 of the work is left.
A can do a piece of work in 15 days.
One day work of A =1/15
B can do a piece of work in 20 days
One day work of B =1/20
(A+B)'s one day work=
They work for 4 days.
So,7/15 of the work is done by A and B
Remain work=
Hence,8/15 of the work is left.
pal23220:
please explain B 20 = 1/20 how can you write B = 24
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