Math, asked by pal23220, 1 year ago

A can do a work in 15 days and B in 20 days if they work on together for 4 days then the fraction of the work that is left is

Answers

Answered by Muskan1101
1
Solution:-
A can do a piece of work in 15 days.
One day work of A =1/15
B can do a piece of work in 20 days
One day work of B =1/20

(A+B)'s one day work=
 =  >  \frac{1}{15}  +  \frac{1}{24}  \\  =  >  \frac{4 + 3}{60}  \\  =  >  \frac{7}{60}
They work for 4 days.
 =  >  \frac{7}{60}  \times 4 \\  =  >  \frac{7}{15}
So,7/15 of the work is done by A and B
Remain work=
 =  > 1 -  \frac{7}{15}  \\  =  >  \frac{15 - 7}{15}  \\  =  >  \frac{8}{15}
Hence,8/15 of the work is left.

pal23220: please explain B 20 = 1/20 how can you write B = 24
Muskan1101: where i have written B=24??
Muskan1101: Ohh soo sorry...by mistake i have written ...but that is 1/20 only..
Similar questions