Question

 A can do a work.in 16 days and B can do the same work in 20 days. They worked together for 5 days and then B left. In how many days will A finish the remaining work?​

Answer 1

Answer:

Per the question, we have:

16A=1

12B=1

Then:

48A=3

48B=4

48A+48B=7

48/7A+48/7B=1

A and B work together for 5 days, doing 5 x 7/48, or 35/48 of the job. This leaves 13/48 of the remaining work to be done. B normally does 1/12th of the work per day. So he will take:

3/48 / 1/12=12 x 13 / 48=13/4 days to finish the remaining work himself ………………

Step-by-step explanation:

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Answer 2

Per the question, we have:

16A=1

12B=1

Then:

48A=3

48B=4

48A+48B=7

48/7A+48/7B=1

A and B work together for 5 days, doing 5 x 7/48, or 35/48 of the job. This leaves 13/48 of the remaining work to be done. B normally does 1/12th of the work per day. So he will take:

3/48 / 1/12=12 x 13 / 48=13/4 days to finish the remaining work himself