A can do a work in 18 days, b in 9 days and c in 6 days. a and b start working together and after 2 days c joins them. in how many days will the job be completed?
Answers
Answered by
5
(A + B + C)’s one day’s work = (1/18) + (1/9) + (1/6) = (1 + 2 + 3) / 18 = 6 /18 = 1/3
(A + B)’s one day’s work = (1/18) + (1/9) = (1 + 2) / 18 = 1 / 6
(A + B)’s 2 days’ work = 2 x (A + B)’s one day’s work = 1 / 3
After two days A, B, C will join together to complete the remaining work 2 / 3
(A + B + C)’s one day’s work is 1/3, ஃ 2 / 3 work will be completed in 2 days by A, B, C
ஃ Total number of days taken to finish the work = 4 days (including A+B’s 2 days work)
(A + B)’s one day’s work = (1/18) + (1/9) = (1 + 2) / 18 = 1 / 6
(A + B)’s 2 days’ work = 2 x (A + B)’s one day’s work = 1 / 3
After two days A, B, C will join together to complete the remaining work 2 / 3
(A + B + C)’s one day’s work is 1/3, ஃ 2 / 3 work will be completed in 2 days by A, B, C
ஃ Total number of days taken to finish the work = 4 days (including A+B’s 2 days work)
Similar questions