A CAN DO A WORK IN 24HR WHILE B CAN DO IT IN 16HR. IF A, B AND C WORKING TOGETHER CAN FINISH IT IN 8HR, IN HOW MAY HOURS CAN C ALONE FINISH THE WORK?
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A's one day's work =1/24
B's one day's work=1/16
(A +B+ C )'s one day's work=1/8
Therefore, C's one day's work = 1/8-(1/24+1/16)
=1/8-5/48
=1/48
Hence, C can finish the work in 48 days.
Hope this will help you :-)
B's one day's work=1/16
(A +B+ C )'s one day's work=1/8
Therefore, C's one day's work = 1/8-(1/24+1/16)
=1/8-5/48
=1/48
Hence, C can finish the work in 48 days.
Hope this will help you :-)
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