Math, asked by adhirajdasgupta13, 6 months ago

A can do a work in 25 days and B can do the same work in 20 days. They work together for 5 days and A goes away. In how many days will B finish the work.

Answers

Answered by Anonymous
0

Answer:

Suppose total work is 1

A=1/15 & B=1/25 for one day work

when both work together

(A+B)= (1/15)+(1/25)=7/60

for 7 days

(7/60)x7=7/15

For remaining work

1-(7/15)=8/15

Answer (8/15)

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Answered by 917998
0

Answer:

11 days

Step-by-step explanation:

In 1- day A and B can do= 1/20+ 1/25 = 9/100.

In 5- days both can do= 9/100 x 5 =45/100.

Number days required by A to finish the remaining work= (55/100)÷(1/20) = 11- days.

========================== Another method A does the work till the end and B does the work for 5- days only.

If the total work if finished in X- days, then

So X/20 + 5/25= 1

5X+ 20= 100

X= 80/5= 16.

So complete work is done in 16- days.

A alone does after B- left= 16–5= 11 days !!!

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