A can do a work in 25 days and B can do the same work in 20 days. They work together for 5 days and A goes away. In how many days will B finish the work.
Answers
Answer:
Suppose total work is 1
A=1/15 & B=1/25 for one day work
when both work together
(A+B)= (1/15)+(1/25)=7/60
for 7 days
(7/60)x7=7/15
For remaining work
1-(7/15)=8/15
Answer (8/15)
PLZ MARK AS BRIANLIEST,FOLLOW ME AND THX FOR THE SUPERB QUESTION
Answer:
11 days
Step-by-step explanation:
In 1- day A and B can do= 1/20+ 1/25 = 9/100.
In 5- days both can do= 9/100 x 5 =45/100.
Number days required by A to finish the remaining work= (55/100)÷(1/20) = 11- days.
========================== Another method A does the work till the end and B does the work for 5- days only.
If the total work if finished in X- days, then
So X/20 + 5/25= 1
5X+ 20= 100
X= 80/5= 16.
So complete work is done in 16- days.
A alone does after B- left= 16–5= 11 days !!!
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