Question

A can do a work in 3 days less than B. A works
it alone for 4 days and then B took over and
completes it. Altogether 14 days were needed to
complete the work, how many days does each of
them take to do the work alone?​

Answer 1

Answer :

A can finish in 15 days

B can finish work in 12 days

Step-by-step explanation:

If B can finish his work in 'x'days,

A can finish work in 3 days less than B,

I. e., x-3

if, A's 1 day work is 1/x-3

then 4 day's of A work is 4/x-3

remaining work will be

1 - 4/x-3 = x-7/x-3

therefore, B can finish 1 work in x days

B can finish 1 work in x-7/x-3 = x * x-7/x-3 days

so x*x-7/x-3+4= 14

x square − 17x+30=0

i.e., A = 15 days

B can finish work in x - 3 = 15 - 3 = 12.

i.e., B = 12 days

Hence, A and B can individually finish the work in 15,12 days respectively.