Question

A can do a work in 3 days less than B. A works it alone for 4 days and then B took over and
completes it. Altogether 14 days were needed to complete the work, how many days does each of them take to do the work alone?
Please answer correctly!!!!!!!!!!​

Answer 1

Let A completes in x days

then B in x+3 days.

Total work ( lcm of x and x+3 ) = x ( x+3)

Since efficiency ∞ 1/time

So , efficiency of A= x+3work / day

And efficiency of B= x work / day .

Efficiency * days = work

( x+3)*4+ x*10 = x( x+3)

x^2- 11x-12 = 0

x= 12

A alone take = 12 days ,B= 15 days

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Answer 2

Answer:

Step-by-step explanation:

can finish work in x - 3 = 15 - 3 = 12. Hence, A and B can individually finish the work in 15,12 days respectively.