Math, asked by kumarsubash1969, 8 months ago

A can do a work in 36 days, B in
18 days and C in 12 days. Every
2nd day B and every 3rd day C,
helps A .Then in how many days
the work will be completed?​

Answers

Answered by shunmugauthaya
0

Answer:

Let to work Total Work = 36

One day work of A = 3636

= 1 unit/day

One day work of B = 3618

= 2 unit/day

One day work of C = 3612

= 3 unit/day

In 3 days cycle total work done is A, A + B, A + C = 1 + (1 + 2) + (1 + 3) = 8 unit/Cycle

∴ 32 units of the work completed in 4 cycle and reminder 4 units of works in next two days.

1 cycle = 3 days

∴ 4 cycle = 12 days

And remaining 4 unit work done in next two days. In days 13, A will work 1 unit and in day 14, A and B will work 3 units.

Total number the day required to complete the work in the given condition is 14 days

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