A can do a work in 6 days and
can do the same work in 9 days.
They started doing the work together A left 2 days before the work was
finished. what time was taken to
finish the work?
Answers
Answer:
in 1 day A completes =1/6 of the work
in 1 day B completes =1/9 of the work
in 1 day (A +B)complete=(1/6 )+(1/9)=5/18of the work
in 2days (A+B) complete =10/18 of the work
now work left =8/18
now ,,B will complete the work in=[8/18]×9=4 days
therefore the total work will be completed in ={2+4} = 6days......
...........xD
Step-by-step explanation:
A's 1 days' work = 1/6 units
B's 1 days' work = 1/9 units
together,
(A + B)'s 1 days' work will be
= (1/6) + (1/9) = 15/54 = 5/18 units
A left the work 2 days before the work was finished . it means only B worked for last 2 days .
so B's last 2 days work = 2(1/9)
= 2/9 units
remaining work
= 5/18 - 2/9 = 1/18 units
1/18 work done by A and B in
= 18/1 × 5/18 = 5 days
total time taken to finish the work
= 5 + 2 = 7 days