A can do a work in 6 hours B can do it 5 hours. A,B and C together can do a work in 2 hours are required find out how many hours are required to complete the work by C?
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Work done by A + B + C = 2 hours
→ (A + B + C)'s one day = 1/2
→ 1/6 + 1/5 + 1/C = 1/2
→ 1/C = 1/2 - (1/6 + 1/5)
→ 1/C = 1/2 -(5 + 6)/30
→ 1/C = 1/2 - 11/30
→ 1/C = (15 - 11)/30
→ 1/C = 4/30
→ 4C = 30
→ C = 15/2
→ C = 7(1/2)
Hence, Work done by C = 7(1/2) hours
Hope it helps!
Brainliest please! :)
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