A can do a work in 8 days and B can do the same work in 12 days in how many days can they do the same work if the work together
Answers
Given that A can do the work in 8 - days.
Work done by A in 1 day = (1/8).
Given that B can do the work in 12 days.
Work done by B in 12 days = (1/12).
Now,
Work done by them in 1 - day = (1/8) + (1/12)
= (1 * 3 + 1 * 2)/24
= 5/24.
Therefore they can complete the work in 24/5 (or) 4 (4/5) days.
Hope this helps!
These types of problems particularly of this pattern can be solved very easily by using this trick:
A can do a work in 8 days
B can do the same work in 12 days
So, let us consider the common total work need to be done by them so;which is LCM of the quantities,
LCM (8, 12)
=24
So total number of days required will be
Days by A = 24/8 =3
Days by B= 24/12 =2
Total = 5 days
So, they can do the same work in 5 days if they work together
Synopsis for the trick:
1) Find the LCM for the number of days
2)Divide them by respective days
3)Add the solution to get the number of days required