a can do a work in 80 days he works at it for 5 days then b do it alone in 50 days in how many days could both do it
pls aolve it fast its urgent
who will give the first answer and the correct one will be marked as brainliest
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Answer:
Now, A can do a piece of work in 80 days. So, let the TOTAL WORK = 80 units.
A -> 80 days = 1 unit/day
So, in 10 days, A has completed 10 units.
Remaining Work = 70 units.
Now, B finishes this in 42 days. So rate of work if B = 70/42 = 53 unit/day
Thus, A + B = 1+5/3 = 8/3
So, TIME TAKEN = 80/8/3 = 30 Days (Answer)
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