a can do a work in 9 days. If b is 50% more efficient than a, then in how many days can b do the same work ?
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in 4.5 days b can do the same work
atifhussain65:
4.5
but the answer is 6 days
ooo please explain
A' s one day work = 1/9 b's 50% more effcient than A A's work =1/9 +50/100(1/9) = 1/9 + 50/900 = 15/90 therefore no. of days required by b =90/15 = 6 days
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