A can do a work of peiece in 40 days and B in 45 days .they work together for 10 days and the B goes away in how many days will A finish the remaining work
Answers
Answer:
21 and 1/9 days
Step-by-step explanation:
A can do the work alone in 40 days
=> Fraction of work done by A in 1 day = 1/40
B can do the work alone in 45 days
=> Fraction of work done by B in 1 day = 1/45
When A and B work together,
they can complete (1/40 + 1/45) of the work in 1 day.
=> Fraction of work completed by A & B in 1 day = 17/360
A and B work together for 10 days
=> Fraction of work completed by A & B in 10 days = 170/360
The fraction of work unfinished by A & B after 10 days
= 1 - (170/360)
= 190/360
Thus, after 10 days
A needs to complete 190/360 of the work.
A can finish 1/40 of the work in 1 day
=> to complete 190/360 of the work he will need (190/360) ÷ (1/40) days
=> A will need (190 * 40)/(1 * 360) days
=> A will need (190/9) days = 21 and 1/9 days.
No. of days that A will take to finish the remaining work = 21