A can do apeice of work in
wock in 40
days. He works at it for 8 days
and then B finishes the work in
16 days. How long will they take
to complete the work if they do it
together.
Answers
Answer:
Here is a simple method for solving such problems where the amount of work is not given. Generally we assume the work to be 1 unit.
Now this time, let's assume the work is of eating chocolates.
Assume the total number of chocolates be 80 (L.C.M of 40, 8, 16)
Condition 1: X eats 80 chocolates in 40 days.
Hence efficiency of X is : 2 chocos / day
Condition 2: X work for 8 days. Then Y work for 16 days
The number of chocolates eaten by X in 8 days : 2*8 = 16
Rest of the chocolates are eaten by Y in 16 days.
Chocolates left= 80-16= 64
So Y eats 64 chocolates in 16 days.
Hence efficiency of Y is : 4 chocos / day
If they work together , Total Efficiency would be (2 chocos / day+4 chocos / day)= 6 chocos / day
No of days they take together to finish 80 chocolates : (80/6)
:13 Days 8 Hours
Step-by-step explanation:
Step-by-step explanation:
He worked at it for 5 days, then B finished it in 21 days. The number of days that A and B take together to finish the work are. ... Work of A in 5 days=5/40=1/8 ... CE ery in 4 days, w 16.
Missing: wock | Must include: wock
Top answer
A csn do a piece of work in 40 daysWork of A in 1 day = 1/40Work of A in 5 days = 5/40 = 1/81/8th part of work is done by ARemaining work = ( 1 - 1/8