A can do apiece of the work in 6 days and B can do same work in 12 days. A worked alone for 2 days and B for 3 days. In how many days will the remaining work be completed if they work together?
Answers
Answer:
i think avneet is right
as she cant be worng
Step-by-step explanation:
1.66 days
Explanation:
Given,
A can do a piece of the work in 6 days
In a day A does (1/6)th of the work
B can do same work in 12 days
In a day B does (1/12)th of the work
A worked alone for 2 days. That is, 2(1/6)th work is done.
A did 1/3rd of total work.
B worked alone for 3 days. That is, 3(1/12)th work is done.
B did 1/4th of total work.
Total work done by A and B alone = 1/3 + 1/4
= (3+4)/12
= 7/12
The work left = 1 - 7/12 = 5/12
Work done by A and B together in a day = 1/6 + 1/12
= 3/12
let x = number of days to complete the work
3/12 * x = 5/12
x = 5/3
x = 1.66 days
#SPJ2
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