A can do apiece of the work in 6 days and B can do same work in 12 days. A worked alone for 2 days and B for 3 days. In how many days will the remaining work be completed ..
Answers
Answer:
In 16/3 days the remaining work will be completed
Step-by-step explanation:
No. of days A takes = 6
No. of days B takes = 12
Total work to be done = LCM of 6 and 12 = 12 units
So, efficiency of A = 6/12 = 1/2
and efficiency of B = 12/12 = 1
ATQ,
Work completed = Work done by A in 2 days + Work done by B in 3 days
= 1/2 X 2 + 1 X 3
= 1 + 3 = 4 units
Work remaining = 12 units - 4 units = 8 units
No. of days = 8 / (1/2 + 1)
= 8 / (3/2)
= 16/ 3
Answer: 1 1/3 days More
additional days.
A speed : 1/6 work per day
B speed : 1/12 work per day
A+ B speed = 1/ ( 1/6+1/12) = 12x6/18= ===>1/4 work per day
Work remaining after two day of A
= 1- 2/6
=2/3
Work remaining after 3 days of B
= 2/3 - 3/12
= 13/36
= 1/3
Days taken for This Remaining work
= 1/3. Divided by 1/4
.= 4/3
or 1 1/3 days More Days
.