Question

A can do apiece of work in 24 days. B is 60% more efficient thanA. The no. of days B to do the same piece of work is​

Answer 1

Answer:

We know that B is 60% more efficient than A. So, the amount of work done by B in one day can be calculated as follows, Work done by B in 1 day =124+60100×124=10240+6240=16240=115.

Step-by-step explanation:

A's 1 day's work =  

24

1

​  

 

B's 1 day's work =  

24

1

​  

+60Percentof  

24

1

​  

=  

24

1

​  

×  

100

160

​  

=  

15

1

​  

 

∴BCandosameworkin15days

∴Bcandodoubleworkin2×15=30days