Math, asked by nisha2890, 9 months ago

 A can do as much work in 6 days as C in 10 days. B can do as much work in 6 days as C can do in 4 days. What time would B require to do a work if A takes 48 days to finish it?​

Answers

Answered by BRAINLYARMY001
3

Answer:

hi

your answer is here !

Step-by-step explanation:

A : C :: 6 : 10

or (A/C) = (3/5)

and

B : C :: 6 : 4

or (B/C) = (3/2), (B/A) =(B/C) x (C/A) = (3/2) x (5/3) = (5/2)

Therefore,

B = (5/2) x A

⇒ (5/2) x 48 = 120 days.

follow \:  \:  \:  \: me

Answered by dlksk8075
2

A took 6 days for the work as B did.

So,B requires the same 48 days to the work

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