Math, asked by aarohi77, 1 year ago

'A' can do some work in 24 days 'B' can do it in 32 days and 'C' can do it in 60 days. They started working together, 'A' left after 6 days and 'B' left after working for 8 days, how Many more days are required to complete the work.

Answers

Answered by palak412
3
Correct Answer = 22 days
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Explanation :
Work done by A in 1 day = 1/24
Work done by B in 1 day = 1/32
Work done by C in 1 day = 1/60

Work done by A, B and C together in 1 day = 1/24 + 1/32 + 1/60 = 43/480
After 6 days, A leaves.
So, work done by A, B and C together in 6 days = 43/80

Now, B and C work together for the next two days before B leaves.
Work done by B and C together in 1 day = 1/32 + 1/60 = 23/480

So, work done by B and C together in 2 days = 46/480 = 23/240

Work remaining after A and B leaves = 1 - (43/80 + 23/240) = 1 - 152/240 = 88/240 = 11/30

So 11/30 of the work is remaining for C to do alone.

C completes 1 work in 60 days

So, C completes 11/30 of the work in 11/30 * 60 days = 22 days
Hope it helps :)
Answered by Akv2
0
30 DAYS ARE REQUIRED TO COMPLETE THE WORK.

PLZ MARK IT AS BRAINLIEST ANSWER AND DROP A ♥
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