Math, asked by navya3484, 1 year ago

a can do work in 10 days B can do a work in 12 days we can do work in 15 days together but a leaves work after two days B leaves work before 3 days in how many days their finish the work​

Answers

Answered by 2003omkaar
0

Answer:

Step-by-step explanation:

A +B do job in 12 days

So work done by A&B in 1 day is 1/12

Similarly work done by B & c in 1 day is 1/15

………….C & A in 1 day is 1/20

Adding we get

Work done by 2A+ 2B +2C =1/12+1/15+1/20

5/60+4/60+3/60=12/60=1/5 in 1 day

Work done by A & B & C in 1 day will be 1/10

A+ B+ C will do 1/10 of work together in 1 day

A +(1/15) =1/10

Solving we get A =1/30

A will do 1/30th of work in 1 day

Or it will take 30 days for A to finish the work alone by himself.

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