A can do work in 12 days B can do work in 15 days. How much days required if they work together?
Answers
(60)/(12/5) or 25 days
step-by-step explaination:
GIVEN:
Let the total work is 60 units which is LCM of (12,15)
A can complete total work or 60 units in 12 days In one day he will complete (60/12) = 5 units
B can complete the same piece of work or 60 units in 15 days then in one day he will complete (60/15) = 4 units
Together they can complete (5+4) = 9 units in one day
They work together for 2 days then in 2 days they completed total = (9*2) = 18 units
After two days B leaves and A alone continue work for one day so in next one day he completed 5 units
Total work completed in 3 days = (18+5) = 23 units
Remaining work = (60–23) = 37 units
This remaining work of 37 units completed by A and C in 5 days when C join A
In 5 days A and C completed = 37 units
In one day they can complete = (37/5) units
A alone can complete = 5 units in one day
It means that C alone can complete (37/5 - 5) = (12/5) units in one day
Total work or 60 units he alone can complete (60)/(12/5) or 25 days
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