a can do work in 18 days b can do tha same work in 36 days with the help of c they did the job in 6 days only then c alone can do the job in ?
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Say Work = LCM(18, 15) = 90 units
A : 18 days to complete 90 units of work i.e. 90/18 = 5 units/day
B : 15 days to complete 90 units of work i.e. 90/15 = 6 units/day
Let ‘x’ be the days in which A can finish the remaining work
Total Work = Work done by A in ‘x’ days + Work done by B in 10 days
90 = 5x + 6(10)
On solving, x = 6 days
...
hope it helps u
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A : 18 days to complete 90 units of work i.e. 90/18 = 5 units/day
B : 15 days to complete 90 units of work i.e. 90/15 = 6 units/day
Let ‘x’ be the days in which A can finish the remaining work
Total Work = Work done by A in ‘x’ days + Work done by B in 10 days
90 = 5x + 6(10)
On solving, x = 6 days
...
hope it helps u
plz mark as brainlist
nbk:
pls read the question clearly how can take 15 days time for b
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