a can filled with water is revolved in a vertical circle of radius 4m so that the water does not fall down. the maximum possible period of revolution is:
a) 1s
b) 2s
c) 3s
d) 4s
Answers
Answered by
74
at the top most position
three forces will act on the water
1 weight in the downward direction
2 normal reaction by bucket in the downward direction
3 centrifugal force in the upward direction
so mg + N =mv2/r
for water just does not fall N ≥ 0
so mg = mv2/r
v =√gr
so time period T = 2∏r/v
=2*3.14*4 /√4g
=3.14*4 /√9.8
=4.01
it is approx.
three forces will act on the water
1 weight in the downward direction
2 normal reaction by bucket in the downward direction
3 centrifugal force in the upward direction
so mg + N =mv2/r
for water just does not fall N ≥ 0
so mg = mv2/r
v =√gr
so time period T = 2∏r/v
=2*3.14*4 /√4g
=3.14*4 /√9.8
=4.01
it is approx.
Answered by
34
Critical velocity at highest point(Vc) =√rg= √4×10=√40m/sec. Distance covered in one revolution (s)=2πr=2×3.14×4m. time taken for a revol. (t)=s÷Vc= 2×3.14×4÷√40= 4sec....(about)
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