A can finish a job in 20 days and B can complete it in 30 days they work together and finish the job if rs..600 is paid as wages find the share of each
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A can finish a job in 20 days
A in 1 day does: 1/20 work
B can finish a job in 30 days
B in 1 day does: 1/30 work
Total work = L.C.M(20,30) = 60
[20 = 2^2 * 5.... 30= 2*3*5...lcm= 2^2*3*5=60]
Efficiency*Days = Work
Efficiency of A = 60/20 = 3
Efficiency of B = 60/30 = 2
Hence, 5=== 600 Rs.
1===600/5 = 120 Rs.
3=== 3*120 = 360 Rs.
2=== 2*120 = 240 Rs.
Hence A receives 360 and B receives 240
Hope it helps.
A in 1 day does: 1/20 work
B can finish a job in 30 days
B in 1 day does: 1/30 work
Total work = L.C.M(20,30) = 60
[20 = 2^2 * 5.... 30= 2*3*5...lcm= 2^2*3*5=60]
Efficiency*Days = Work
Efficiency of A = 60/20 = 3
Efficiency of B = 60/30 = 2
Hence, 5=== 600 Rs.
1===600/5 = 120 Rs.
3=== 3*120 = 360 Rs.
2=== 2*120 = 240 Rs.
Hence A receives 360 and B receives 240
Hope it helps.
Answered by
1
Answer:16.66%
Step-by-step explanation:
C.P of radio =Rs.600
S.P of radio=Rs.700
Gain =S.P-C.P ,700-600=100
Gain= Gain ×100÷C.P
Gain=100×100÷60
Gain=16.66%
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