Question

A can finish a piece of work in 15 days and B
can do it in 10 days. They worked together for
2 days and then B goes away. In how many
days will A finish the remaining work?​

Answer 1

Answer:

☆Given,

》》A's 15 day's work

》》B's 10 day's work

☆ To Solve,

》》Time taken by A to finish the remaining work.

☆ Solution:

☆A's 1 day's work = 1/15

☆B's 1 day's work = 1/10

☆(A + B)'s 1 day's work = 1/15 + 1/10 = 2 +3/30 = 5/30 = 1/6 [LCM of 15 and 10 is 30]

☆(A + B) 2 day's work = 1/6 × 2 = 1/3

♡♡ Finally,

Time taken by A to finish the remaining work = 1/3 × 15 = 5

♤♤Clearly,

A can will finish the remaining work in 5 days.